shell_exec() in php..is the usage similar to shell script
| hey guys, i am interested in using shell_exec but somehow it doesn't give me the output like i want. Let me explain a little bit about what i did and what i am interested to do. I have created a shell script which can execute a c program and this c program will create a text file according to some conditions. so this is my shell script and i named it as test.sh: echo -n "enter the value to pass to c programm : " read var echo "The value is : $var" $(./myfile $var) and below is my c program: #include <stdio.h> #include <stdlib.h> int main(int arg,char *argv[]) { int option=atoi(argv[1]); int i=0; int d[10]={1,2,3,4,5,6,7,8,9,10}; FILE *fp; char file_one[]="text.txt"; char file_second[]="text1.txt"; printf("option:%d\n",option); if(option==1) { fp=fopen(file_one,"a"); if(fp==NULL) exit(1); } if(option==2) { fp=fopen(file_second,"a"); if(fp==NULL) exit(1); } for(i=0;i<10;i++){ fprintf(fp,"x[%d]:%d,",i,d[i]); } return 0; } i compiled my c program using gcc -o myfile myfile.c as well as compile my shell script using chmod +x test.sh.then i executed my shell script using ./test.sh.Then it will ask me to give the value to my variable var.if i enter whatever value as the value of var,this value will be later passed to c program as the main argument.i convert the main argument argv[1] to integer using atoi(argv[1]).so by doing this i will give value to the variable option.then i used the if statements and provided conditions to them.if the condition true,the txt file will be created.for example i give the value of 1 to var in my shell script, and this value of 1 will be pass to argv[1].as argv is converted to integer,the option now will posses the value of 1.As option equal to 1 the 1st if statement will evaluate option==1 as true and as a result text.txt will be created.Otherwise if i enter 2,the text1.txt will be created Using the same idea, i plan to used my php to do the same as shell script. This is my php code <html> <title>File Option</title> <body> <h1>Give a suitable value</h1> 1:File_One 2:File_Two <form method="post"> <p>Num1:<input type="text" name="arg1" size="40" value=""/></p> <p><input type="submit" name="submit" value="GO"/> </form> <?php if(isset($_POST['arg1'])) { $num1=$_POST['arg1']; if($num1){ $output=system("./myfile $num1"); print "<p>$output</p>"; } } ?> </body> </html> So basically the idea is if i enter 1 in the input and click GO,this value of 1 will pass to the main argument using the command shell_execution(./myfile $num1) and the text.txt will be created.unfortunately this text.txt has not created..i dont know why and thats why i decided to seek some ideas here..thanks in advanced |
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